$s_agree_value = $s_agree_value + $vote_agree_users[$answer_id]['reputation_factor'];$vote_agree_users[$answer_id]，同一个答案ID，赞同的Users不一定只有一个，这样直接以下标来获取，只能取到一个值。 再追根溯源，在answer.php里面，获取答案对应的投票的函数就已经有问题了：
if ($users = $this->fetch_all('answer_vote', "answer_id IN(" . implode(',', $answer_ids) . ") AND vote_value = 1"))
{
foreach ($users as $key => $val)
{
$data[$val['answer_id']] = $val;
}
}
$users变量里面，可能出现多条answer_id相同的记录，比如：
[0] => Array ( [voter_id] => 5 [answer_id] => 12 [answer_uid] => 5 [vote_uid] => 7 ...
[1] => Array ( [voter_id] => 13 [answer_id] => 12 [answer_uid] => 5 [vote_uid] => 6 ...
此时不宜直接用map来存储数据了，否则只能存其中的一个。应该给数组再加一个维度才行。
没学过php，分析的不一对，请官方看下，谢谢。AI智能回复搜索中，请稍后...
1 回答
public function get_vote_agree_by_answer_ids($answer_ids)
{
if (!is_array($answer_ids))
{
return false;
}
array_walk_recursive($answer_ids, 'intval_string');
if ($users = $this->fetch_all('answer_vote', "answer_id IN(" . implode(',', $answer_ids) . ") AND vote_value = 1"))
{
foreach ($users as $key => $val)
{
$data[$val['answer_id']][] = $val;
}
}
return $data;
}
if ($vote_agree_users[$answer_id]) { foreach ($vote_agree_users[$answer_id] AS $key => $val) { $s_agree_value = $s_agree_value + $val['reputation_factor']; } }反对系数也一样修改，就不贴了
